Andreas van Cranenburgh, 0440949
Dennis Roof, 0490474

1.
%radio -> rAdIjO
ca( [r, a, d] / 'A' ).
ca( [d, i, o] / 'I' ).
ca( [i, o, ' '] / j ).
ca( [o, ' ', ' '] / 'O' ).

%ideaal
ca( [_, i, d] / 'I' ).
ca( [_, a, a] / 'A' ).
ca( [a, a, _] / ' ' ).

%appelflap
ca( [_, p, p] / 'P' ).
ca( [p, p, _] / ' ' ).
ca( [_, f, _] / v ).

%trottoir
ca( [_, t, t] / 'T' ).
ca( [t, t, _] / ' ' ).
ca( [o, i, r] / 'A' ).
ca( [_, o, i] / w ).

%louche
ca( [o, u, c] / e ).
ca( [u, c, h] / s ).
ca( [e, c, h] / s ).
ca( [c, h, e] / j ).
ca( [s, h, e] / j ).
ca( [s, h, u] / j ).
ca( [c, h, u] / j ).
ca( [h, e, _] / u ).
ca( [j, e, _] / u ).



2. de antwoorden staan in de syntax van het zelfgemaakte programma:
# example rule table: N E M S W new_M
# _ is wildcard (inspired by Prolog)

a.
# move image down:
movedown = ["1____1",
"0____0"]

b.
#invert image:
invert = ["__1__0",
"__0__1"]

c.
# move image down and invert:
movedowninvert = ["1____0",
"0____1"]

d1.
#show edges:
edges = ["111110"]

d2.
#blur
blur = ["001000",
"001010",
"001100",
"001110",
"011000",
"011010",
"011100",
"101000",
"101010",
"101100",
"111000"]